比如一个文件里有N行这样的:
Sun Jan  4 00:16:22 2009...................略

我想用sed提取所有行上的2009那列咋写啊?不能用awk ,cut.
或者还有其它命令可以提吗?谢谢.

确定是第几列 就写个土一点的regex放在sed了 就好了

麻烦给个命令吧,我对sed不太熟悉呵呵.多谢.

你数据多贴几行出来吧，最好全的。

Mon Jan 5 00:12:43 2009 [**431085535.17488**]
Mon Jan 5 00:13:20 2009 [**431085535.17488**]
Mon Jan 5 00:14:25 2009 [**431085535.17488**]
Mon Jan 5 00:21:10 2009 [**431086067.17488**]
Mon Jan 5 00:41:22 2009 [**431087280.17588**]
Mon Jan 5 00:41:45 2009 [**431087303.17583**]
Mon Jan 5 00:46:19 2009 [**431087577.17583**]
Mon Jan 5 00:57:03 2009 [**431088221.17581**]
Mon Jan 5 01:05:33 2009 [**431088729.17582**]
Mon Jan 5 01:07:18 2009 [**431088836.17494**]
Mon Jan 5 01:07:18 2009 [**431088836.17493**]
Mon Jan 5 01:31:53 2009 [**431090307.17490**]
Mon Jan 5 01:58:39 2009 [**431091911.17671**]
Mon Jan 5 02:16:44 2009 [**431093002.17665**]
Mon Jan 5 03:07:09 2009 [**431096026.17672**]
Mon Jan 5 03:28:49 2009 [**431097325.17668**]
Mon Jan 5 04:26:45 2009 [**431100801.17756**]
Mon Jan 5 04:56:28 2009 [**431102582.18390**]
Mon Jan 5 06:37:55 2009 [**431108673.18655**]
Mon Jan 5 06:43:40 2009 [**431109019.18655**]
Mon Jan 5 06:57:53 2009 [**431109862.19212**]
Mon Jan 5 07:03:52 2009 [**431110228.18661**]
Mon Jan 5 07:27:47 2009 [**431111662.18387**]
Mon Jan 5 07:45:41 2009 [**431112737.18661**]
Mon Jan 5 07:52:25 2009 [**431113143.19212**]
Mon Jan 5 07:54:01 2009 [**431113235.18654**]
Mon Jan 5 08:00:08 2009 [**431113604.19271**]
Mon Jan 5 08:00:08 2009 [**431113603.19211**]
Mon Jan 5 08:00:08 2009 [**431113604.19208**]
Mon Jan 5 08:00:08 2009 [**431113604.19203**]
Mon Jan 5 08:00:08 2009 [**431113604.19210**]
Mon Jan 5 08:00:08 2009 [**431113603.19209**]
Mon Jan 5 08:00:09 2009 [**431113604.18655**]
Mon Jan 5 08:00:09 2009 [**431113603.18386**]

我要取第6列,[**431113603.18386**]这样的.

sed 's/.* //'

awk '{print $NF}'

cat urfile | sed 's/.*[/[/' > anewfile

[ 本帖最后由 nlspii 于 2009-1-5 14:21 编辑 ]

才看见不让用awk.....

[ 本帖最后由 smallstar001 于 2009-1-5 14:28 编辑 ]